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60x+-2x^2-10x=2x^2+14x
We move all terms to the left:
60x+-2x^2-10x-(2x^2+14x)=0
We add all the numbers together, and all the variables
-2x^2+50x-(2x^2+14x)=0
We get rid of parentheses
-2x^2-2x^2+50x-14x=0
We add all the numbers together, and all the variables
-4x^2+36x=0
a = -4; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-4)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-4}=\frac{-72}{-8} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-4}=\frac{0}{-8} =0 $
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